Solve for x: Substitute Multiply the exponents on the left side. Invert the right side and change the sign of the exponent. Now since the bases (3) are equal, the exponents must be equal, so...

Now we solve for x. Adding 3x to each side we get: 5x = -6 Dividing by 5 we get: If we are clever enough to see that 9 is a power of 1/27 (and vice versa) then the solution is a little faster …

the original equation is log(x-2) + log(9-x) 1 in order for the expression inside the log to be greater than 0, then x has to be greater than 2 and x has to be smaller than 9. now you have 4 …

Given that 3^x=9^x+1 work out the value of x. My wrong workings: 3x=9x+1 X+1squareroot 3x=9 X=9-x+1squareroot3x It must be . You need to USE PARENTHESES. Write back and I'll solve …

Question 803297: If 9^x-1 = 7 then what is 3^2x+3 The ^'s mean exponent and the 2x+3 at the end is ALL part of the exponent of 3. So it should belike 3 TO THE POWER OF "2x+3" Answer …

Solve the Equation 9x-1=1 - Answer | Math Problem Solver - Cymath ... \\"Get

27^x =9^-x-1-----There's more than 1 approach to this. The simplest is: Both 27 and 9 are integral powers ...

log9 1= x hoping you mean log base 9 of the number 1 equals x log9 (1) = x this is equivalent to 9^x = 1 use conversion of base formula: logb (x) = logk (x)/logk (b), where b is old base and k …

(x-10)(x-1) = 0 From the Zero Product Property we know that this product is zero only if one fo the factors is zero. So: x-10 = 0 or x-1 = 0 Solving each of these we get: x = 10 or x = 1 When …

Question 803292: If 9^x-1 = 7 then what is 3^2x+3 The ^'s mean exponents Answer by Alan3354(69443) ...